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# Write the complex number in polar form. express the argument in degrees. 4i a. 4(cos 0° + i sin 0°) b. 4(cos 270° + i sin 270°) c. 4(cos 90° + i sin 90°) d. 4(cos 180° + i sin 180°)

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In analytic geometry, there are two types of roots: real roots and complex roots. Imaginary roots are those with the term 'I'. These are the complex numbers that can be found on the number line, what is called imaginary. The term 'I' is equal to the expression √(-1). So when you solve these equations, just treat the complex numbers as it is that are variable.The only way to resolve these is to test each option, so that your final answer would be 4i. These are important equivalents to know:sin 0° = 0 cos 0° =1sin 90° =1 cos 90° =0 sin 180° =0 cos 180° = -1sin 270° = -1 cos 270° = 0Using these values, we will simplify each election.A. 4(1 + i (0)) = 4B. 4(0 + (-1)) = -4iC. 4(0 + i (1)) = 4iD. 4((-1) + i (0)) = -4the answer is C.