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# Which shows one way to determine the factors of 4x3 + x2 - 8x - 2 by grouping? A. x2 (4x + 1) - 2 (4x + 1) B. x2 (4x - 1) + 2 (4x - 1) C. 4x2 (x + 2) - 1 (x + 2) D. 4x2 (x - 2) - 1 (x - 2) Please help ASAP!

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\left[x \right] = \left[ \frac{-1}{4}+\frac{x2}{8}+\frac{x3}{2}\right][x]=[4-1+8x2+2x3]4x2 (x + 2) - 1 (x + 2)