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Which of the following is a possible Noble gas notation? [Xe] 6s26p6 [Kr] 5s25d85p6 [Xe] 6s25d106p4 [Kr] 5s24d105p6

Ronald Miller

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Daniel King on December 9, 2018

The answer is: [Kr] 5s24d105p6.1) [Xe] 6s26p⁶ is not correct, because the element with the atomic number 62 (54 + 8) is samarium with electronic configuration [Xe] 6s24f⁶.De xenon (Xe) is a noble gas with atomic number 54, which means it has 54 protons and 54 electrons. The electronic configuration of the atom of xenon: ₅₄Xe 1s2 2s2 2p⁶ 3s2 3p⁶ 3d1⁰ 4s2 4p⁶ 4d1⁰ 5s2 5p⁶. 2) [Kr] 5s25d⁸5p⁶ is not correct, because the element with atomic number 52 (36 + 16) is tellurium.The tellurium (Te) is an element with atomic number 52 (52 protons and 52 electrons), is in group 16 (chalcogens) and period 5 (principal quantum number n = 5, which means that it has 5 electron shell) of the Periodic table. The electronic configuration of tellurium atom: ₅₂Te 1s2 2s2 2p⁶ 3s2 3p⁶ 3d1⁰ 4s2 4p⁶ 4d1⁰ 5s2 5p⁴ or [Kr] 4d1⁰5s25p⁶.Krypton is a chemical element with symbol Kr and atomic number 36, which means that it has 36 protons and 36 electrons.The electronic configuration of the atom of krypton: ₃₆Kr 1s2 2s2 2p⁶ 3s2 3p⁶ 3d1⁰ 4s2 4p⁶.3) [Xe] 6s25d1⁰6p⁴ is not correct, because the element with the atomic number 70 (54 + 16) is ytterbium (Yb) with electronic configuration [Xe] 6s24f1⁴.4) [Kr] 5s24d1⁰5p⁶ is correct, because the element with the atomic number 54 (36 + 18), krypton (Kr) with the electronic configuration 1s2 2s2 2p⁶ 3s2 3p⁶ 3d1⁰ 4s2 4p⁶ or [Kr] 5s24d1⁰5p⁶.


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