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What is the theoretical yield in grams for this reaction under the given conditions?1.12 g H2 is allowed to react with 9.72 g N2, producing 1.00 g NH3.?

Timothy Norman

in Chemistry

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William Cain on September 9, 2018

Theoretical yield in grams for this reaction under the given conditions is 6.341 gramscalculationwrite reaction equation 3 H2 + N2 → 2NH3find the moles of each reactantmoles =mass/molar mass moles of H2 = 1.12 g/2 g/mol = 0.56 mol moles of N2 = 9.72 g/28 g/mol = 0.341 molesby use of the mole ratio between H2 and NH3, which is 3: 2 moles NH3 = 0.56 x 2/3= 0.373 molesby use of the mole ratio between N2 to NH3, it is 1: 2 moles NH3 = 0.341 x2/1 = 0.682 molesthis relationship show that H2 is the limiting reagent therefore the moles of NH3 = 0.373 molesThe theoretical mass = moles of NH3 x molar mass of NH3molar mass of NH3 = 14+ 3 = 17 g/moltheoretical mass is, therefore, = 17 g/mol x 0.373 moles =grams 6.341


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