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What is the range of the function f(x) = 3x2 + 6x – 8?

Blair Lewis

in Mathematics

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Nicholas Rivera on February 7, 2019

Find the minimum and maximum value of y, because that is what the range of iswe see that it opens by 3 is positivex value of vertex is -b/2a when f(x)=ax^2+bx+cf(x)=3x^2+6x-8vertex is -6/(2*3)=-6/6=-1find value and subsituiong to xf(-1)=3(-1)^2+6(-1)-8f(-1)=3(1)-6-8 f(-1)=3-14f(-1)=-11range is from -11 to infinity


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