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What is the pressure of 0.540 mol of an ideal gas at 35.5 L and 223 K? Use mc031-1.jpg and mc031-2.jpg. 0.715 kPa 2.45 kPa 28.2 kPa 62.7 kPa

Jodi Brooks

in Chemistry

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Nicholas Rivera on November 18, 2018

Given the information:the Number of Moles of ideal gas, n = 0.540 Volume, V = 35.5 LTemperature, T = 223 KTo determine:the Pressure P of the ideal gas in the conditionsExplanation:The ideal gas equation relates the state of the parameters P, V and T through the relationship:PV = nRThere R is the gas constant = 8.314 L. kPa.K⁻1mol⁻1 P = nRT/PV = 0.540 mol * 8.314 L. kPa.K⁻1mol⁻1*223 K/35.5 L = 28.2 kPaAns: the pressure of The ideal gas at the given conditions is 28.2 kPa


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