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What is the oxidation state of an individual phosphorus atom in po33−?

Kristi Hammond

in Chemistry

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Ronald Miller on January 11, 2018

Composed of: PO₃3⁻Go, the Oxidation state of P = xThen, x - 2 * 3 + 3 = 0 [ O. S. of O = -2 ]x - 6 + 3 = 0 or x - 3 = 0 x = 3in short, His Answer would be: 3Hope this helps!


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