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What is the mass of 0.7891 mol of ferric oxide (Fe2O3)?

Victoria Fowler

in Chemistry

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Chelsea Hayes on July 27, 2018

The mass of 0.7891 mol of ferric oxide (Fe2O3) is 125.94 grams calculationmass of Fe2O3 is calculated using the moles of Fe2O3/ molar mass of Fe2O3 formulamoles of Fe2O3 = 0.7891 molesmolar mass of Fe2O3= (55.8 x2) + (16 x 3) =159.6 g/molmass is, therefore, =0.7891 mol x 159.6 g/mol=125.94 grams


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