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What is the length of the altitude drawn to the hypotenuse? The figure is not drawn to scale. a) b) 70 c) d) 19 Download png

Blair Lewis

in Mathematics

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Whitney Matthews on March 28, 2018

we know thatin triangle ABCcos (alpha)=H/(14+5)--------> cos (alpha)=H/(19) the equation 1in triangle BDCcos (alpha)=14/H equation 21=2H/(19)=14/H-------> H2=19*14---------> H2=266------> > H=√266H=16.31 unitscos (alpha)=14/16.31----------> cos (alpha)= 0.8584 alpha=arccos(0.8584)=30.86°we know triangle BDCsin(alpha)=h/H---------> h=sin(alpha)*Hh=sin(30.86)*16.31----------> H=8.37 units---------> √70 unitsthe answer is option a) √70


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