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What is the general form of the equation for the given circle centered at O(0, 0)? a) x2 + y2 + 41 = 0 b) x2 + y2 − 41 = 0 c) x2 + y2 − 41 = 0 d) x2 + y2 + x − y − 41 = 0Download png

Deborah Edwards

in Mathematics

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Ralph Lopez on July 17, 2018

hello :an equation of the circle with Center at the Or(a,b) and ridus : r is : (x-a)2 +(y-b)2 = r2 in this test : a =0 and b = 0 (Center at the origin) r = AO r2 = (AO)2 r2 = (4-0)2 +(5-0)2 = 16+25=41 an equation of the circle that satisfies the stated conditions. The center at the origin, passing through B(4, 5) is : x2 +y2 = 41x2 +y2 - 41=0


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