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What is the empirical formula for a compound if a sample contains 3.72g of P and 21.28g of Cl?-PCl5-PCl3-P2Cl10-P2Cl5

Chelsea Hayes

in Chemistry

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Megan Page on February 2, 2018

Since 3.72 g of P and 21.28 g of Cl, the conversion of these to moles: ( 3.72 g (P)(mol P/30.97 g P) = 0.12 mol of P (21.28 g Cl)(mol Cl/35.45 g Cl) = 0.60 mol Cl P:Cl = 0.12/0.60, thus P: Cl =1/5 Therefore, PCl5


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