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What is the concentration of the unknown h3po4 solution? the neutralization reaction ish3po4(aq)+3naoh(aq)→3h2o(l)+na3po4(aq) -g,com?

Justin Parker

in Chemistry

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Ronald Miller on April 28, 2018

First, we need to get the moles of NaOH:when moles of NaOH = volume * molarity = 0.02573 L * 0.11 M = 0.0028 moles of the reaction equation:H3PO4(aq) + 3NaOH → 3 H2O(l) + Na3PO4(aq)we can see that when 1 mol of H3PO4 reacts with→ 3 moles of NaOH ∴ X moles of H3PO4 reacts with → 0.0028 moles of NaOH∴ moles of H3PO4 = 0.0028 mol / 3 = 9.4 x 10^-4 molnow we can obtain the concentration of H3PO4:∴[H3PO4] = mol H2PO4 / volume = 9.4 x 10^-4 / 0.034 L = 0.028 M


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