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What is the 6th term of the geometric sequence where a1 = 128 and a3 = 8?

Curtis Rhodes

in Mathematics

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Jeffrey Rodriguez on October 7, 2018

I have not learned this, but if I had to guess...a1 = 128a2 = 32a3 = 8a4 = 2a5 = 1/2a6 = 1/8Therefore I think that the 6 term is 1/8. The pattern is that it is divided by 4.


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