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What are the sine, cosine, and tangent of 5 pi over 4 radians? sin θ = square root 2 over 2; cos θ = negative square root 2 over 2; tan θ = −1 sin θ = negative square root 2 over 2; cos θ = negative square root 2 over 2; tan θ = 1 sin θ = square root 2 over 2; cos θ = negative square root 2 over 2; tan θ = 1 sin θ = negative square root 2 over 2; cos θ = square root 2 over 2; tan θ = −1

Daniel King

in Mathematics

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Amanda Johnson on September 9, 2018

Please note that we can draw the angle by the addition of 5 's, as shown in the picture which shows the unit circle.The coordinates of a be (-a, -b) , then its reflection in the first quadrant is the angle (45°) with coordinates (a, b).We know that , therefore the coordinates (-a, -b), which are the cosine and sine, respectively, are:.From the identity tan(x)=sin(x)/cos(x), we easily see that the tangent is 1.Answer:.


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