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What are the coordinates of the vertex for f(x) = 3x2 + 6x + 3? (−1, 0) (3, 6) (0, −1) (6, 3)

Jodi Brooks

in Mathematics

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Cynthia Baker on July 15, 2018

For ax^2+bx+c=0 x value of vertex is -b/2ay value is the value of x subsituted3x^2+6x+3a=3b=6-6/(2*3)=-6/6=-1x coordinate is -1plug is inf(-1)=3(-1)^2+6(-1)+3f(-1)=3(1)-6+3f(-1)=0the vertex is at (-1,0)


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