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# Using the conversion factor from eV (electron volts) to joules, determine which energy line for an electron dropping from one energy level to another would show a line at 435 nm in an emission spectrum. Use the formulas and the energy level information below to answer the question. Needed constants: 1.00eV = 1.6 * 10^-19 J c = 3.00 * 10^8 m/s h = 6.63 * 10^-34 J*s Energy Level Values: E6: E= -0.378 eV E5: E= -0.544 eV E4: E= -0.850 eV E3: E= -1.51 eV E2: E= -3.403V

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The formula used to solve the problem is:E = hc/λThe given values can be subsituted in the equation to sovle for the energy:E = (6.63 x 10^-34 J-s) (3 x 10^8 m/s) / 435 x 10^-9 I = 4.5724 x 10^-19 Jconverting electron voltsE = 4.5724 x 10^-19 J * 1.00 eV / 1.6 * 10^-19 JE = 2.86 eVThe nearest power line isE2