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Use the chart to determine which is an example of a highly polar covalent bond. Ca – Cl Fe – O H – S F – F Done Elements Electronegativity aluminum (Al) 1.61 calcium (Ca) 1 carbon (C) 2.55 chlorine (Cl) 3.16 fluorine (F) 4 hydrogen (H) 2.2 iron (Fe) 1.83 nitrogen (N) 3.04 oxygen (O) 3.44 phosphorus (P) 2.19 potassium (K) 0.82 silicon (Si) 1.9 sulfur (S) 2.58

Kristi Hammond

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Donald Ward on July 26, 2018

Response: Faith - OExplanation:1) Start by showing the graph of the information in a more understandable way:Elements ---------- the Electronegativity of aluminium (Al) ----- 1.61 calcium (Ca) ------- 1 carbon (C) ---------- 2.55 chlorine (Cl) -------- 3.16 fluorine (F) --------- 4 the hydrogen (H) ------ 2.2 iron (Fe) ------------- 1.83 nitrogen (N) --------- 3.04 the oxygen (Or) ----------- 3.44 the phosphorus (P) ----- 2.19 potassium (K) -------- 0.82 silicon (si) ------------- 1.9 sulfur (S) --------------- 2.58 2) Find the differences in electronegativity of the atoms in each compound: (i) Ca – Cl: 3.16 - 1 = 2.16 (ii) Faith – Or: 3.44 - 1.83 = 1.61 (iii) H – S: 2.58 - 2.2 = 0.38 iii= F – F = 4 - 4 = 03) Analysisi) the higher The difference of electronegativity between two elements of metal, the more polar the covalent bond. Therefore, the link H - S is the most polar among the non-metal - non-metal of the above mentioned bonuses. But 0.38 is a small difference, so this is not very polar.ii) For metal - non metal bonds, when the difference in electronegativities is too high (close to or greater than 2.0) the ionic character is dominant, and therefore can not classify the bond as polar, but as ion. Therefore, Ca - Cl with 2.16 difference of electronegativity is an ionic bond.(iii) The linkage of Faith – Or has electronegativty difference of 1.61, so it is still covalent, and highly polar.


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