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# This graph shows two curves pertaining to a hydrogen s orbital.

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Answer 1 : According to the full question is attached in the response,The radial wave function is denoted by which is shown with orange crosses through the zero point. Also, In the radio of the nodes, which are spherical shells of some radial distance from the core there is no electron will be found.Also, the radial of the curve of probability distribution is denoted as shown in blue colour is observed that the contact is zero, and shows the location of the radial node.Therefore, the total number of nodes includes both the types that have radial and angular nodes are represented by 'n'. It is observed that for any orbital atomic, the total number of nodes will be n-1 .Taking into account the orbital's of the hydrogen, which has zero, the angular momentum (l), (l=0), since it has zero angular nodes. Therefore, there will be only radial nodes, which is(n−1 = total number of nodes in radial orbitals s)According to the picture, there are 4 radial nodes are shown, then n = 5 (n-1 = 4; therefore, n = 5), This represents the orbital 5s.Answer 2) The radial nodes observed in the I am seeing radial nodes , , and .where represents the hydorgen bohr atomic radius = 0.0529177 nmExplanation : it is very easy to observe the given graph and find the approximate values of the radial nodes, which do not require any equation to solve. The equation can be used to find the radial nodes if provided along with the question. Although mere speculation, one can find the answer.