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The reaction below has an equilibrium constant kp=2.2×106 at 298 k. 2cof2(g)⇌co2(g)+cf4(g) calculate kp for the reaction below. cof2(g)⇌12co2(g)+12cf4(g)

Whitney Matthews

in Chemistry

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Samantha Barber on February 15, 2019

I believe that the correct 2nd reaction is:cof2(g)⇌1/2 co2(g)+1/2 cf4(g), where we can see that it is exactly half of the originalTherefore the new Kp is:the new Kp = (ex Kp)^(1/2)new Kp = (2.2 x 10^6)^(1/2)new Kp = 1,483.24


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