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The quadratic function h(t)=-16.1t^2 + 150 models a balls height, in feet, over time, in seconds, after it is dropped from a 15 story building. - From what height, in feet, was the ball dropped? -After how many seconds, rounded to the nearest hundredth, did the ball hit the ground?

Jeffrey Rodriguez

in Mathematics

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Annie Barnes on January 15, 2018

In order to find the height from which the ball falls, you have to find the height, or h(t) at time t is equal to zero.So plug in t=0 in your quadratic equation:h(0) = -16.1(0^2) + 150h(0) = 0 +150h(0) = 150 ft is the height from which the ball is dropped. When the ball hits the ground, the height is zero. So plug in h(t) = 0 and solve for t.0 = -16.1 t^2 + 15016.1 t^2 = 150t^2 = 150/16.1 t = sqrt(150/16.1)t = ± 3.05, Since time cannot be negative, your answer is positive, that is to say, the solution t = 3.05


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