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The half-life of phosphorus-32 is 14.26 days. calculate its decay constant. express the decay constant numerically in inverse days.

James Washington

in Chemistry

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Timothy Norman on July 24, 2018

When this is the first-order reaction radioactive decay:and according to the first-order rate equation:㏑(Ao/A) = K tand when Ao = is the starting point concentrationand A = is the concentration at time tand K is the rate constant t is the elapsed time = 14.26 daysfor 1 half-life ∴ Ao/A = 2by substitution:㏑2 = K * 14.26 days∴ K = 0.0486 days^-1


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