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The generic metal hydroxide M(OH)2 has Ksp = 7.85×10−18.What is the solubility of M(OH)2 in pure water?

Kaitlin Dean

in Chemistry

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Nicholas Rivera on July 19, 2018

A substance's solubility product, Ksp, is the mathematical product of its dissolved ion concentrations raised to the power of their stoichiometric coefficients. The equation of dissociation of a generic metal hydroxide would be as follows:M(OH)2 = M2+ + 2OH-calculate the solubility of the following way:7.85 x 10^-18 = [M2+] [OH]^27.85×10^-18 = [x] [2x]^27.85×10^-18 = 2x^3x = 1.58 x 10^-6 MHope this answers the question. Have a good day.


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