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# The decomposition of n2o5 can be described by the equation given these data for the reaction at 45°c in carbon tetrachloride solution, calculate the average rate of reaction for each successive time interval. 0 155

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Please find the attached image it is assumed that missing in your question:when the decomposition reaction is:2N2O5 → 4 NO2 + O2(g)and when the average of the rate of the reaction formula is:average rate = -1 / a * (Δ[a] / Dt) where A is the change and the difference in t Mand change or difference in the SSo,1) from 0 to 195 s:when the speed of reaction = (-1/a) (Δ[a]/Dt)where n = number of moles, and we can obtain the balanced equation = 2 and ΔA = 1.72 M-1.95 Mand Δt = 195s - 0 s∴ by substitution:the reaction rate = (-1/2)(1.72 M - 1.95 M) / (195s-0s) = 5.9 x 10^-4 M/s2) from 195 to 406 s:we are going to do the same as 1 ΔA =1.51 M-1.72 MΔ t = 406s-195sthe the speed of reaction = -1 / 2 (1.51 M -1.721 M)/(406s-195s) = 5.21 x 10^-43) 406 to 755s:ΔA = 1.21-1.51 M Dt = 755 - 406 the speed of reaction = -1/2 *(1.21-1.51)*(755-406) =4.3 x 10^-4