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Solve for n: 21k – 3n + 9p > 3p + 12. A.n > 2p + 7k - 4 B.n < 2p + 7k - 4 C. n > -4p - 7k + 4 D. n < -4p - 7k + 4

Victoria Fowler

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Whitney Matthews on October 21, 2018

Solve for n.21k−3n+9p>3p+12Add -21k on both sides.21k−3n+9p+−21k>3p+12+−21k−3n+9p>−21k+3p+12Add -9p to both sides.−3n+9p+−9p>−21k+3p+12+−9p−3n>−21k−6p+12Divide both sides by -3.−3n/-3 > −21k−6p+12/−3n < 7k+2p−4


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