Hot Student Stories
top-5-grammar-and-spelling-checkers-to-rock-in-2019

Pentacarbonyliron(0) (fe(co)5) reacts with phosphorous trifluoride (pf3) and hydrogen, releasing carbon monoxide: fe(co)5+2pf3+h2→fe(co)2(pf3)2(h)2+3co if 6.0 g of fe(co)5 reacts with 4.0 g of pf3 and 4.0 g of h2, which is the limiting reagent?

Theresa Perry

in Chemistry

follow
followin
1 answer
15 views

1 answer


Bethany Evans on December 4, 2018

The limiting reagent can be determined by calculating the moles supply / mol stoich ratio and the lower is the limiting reagent.Fe(CO)5 ratio = [6 g / 195.9 g/mol] / 1Fe(CO)5 ratio = 0.0306 PF3 ratio = [4 g / 87.97 g/mol] / 2PF3 ratio = 0.0227 H2 ratio = [4 g / 2 g/mol] / 1A2 ratio = 2, we can see that PF3 has the lowest ratio, so that is the limiting reagent.


Add you answer