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Liquid sodium is being considered as an engine coolant. How many grams of liquid sodium (minimum) are needed to absorb 1.00 MJ of energy (in the form of heat) if the temperature of the sodium is not to increase by more than 10.0 °C? Use CP = 30.8 J/(K·mol) for Na(l) at 500 K.

Mindee Nelson

in Chemistry

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Karen Wright on August 15, 2018

The energy absorbed is calculated as the product of the mass, the specific capacity and the change in the temperature. It is expressed as:H = nCpΔTwhere n is the moles of the substance, Cp is the specific heat and ΔT is the change in temperature.1 x 10^6 J = n ( 30.8 J/mol k )(10 K)n = 3246.75 molmass = 74642.86 g of liquid sodium


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