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If the vertical component of velocity for a projectile is 7.3 meters/second, find its hang time.
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The height of the projectile is given by:h = ut - 0.5at2The height is 0 twice, once at t = 0 and in the second time, at the time when the trip is complete, or t = hang time.0 = 7.3 t - 0.5(9.81)t2t = 1.49 seconds