If the organ pipe is cut in half, what is the new fundamental frequency? if the organ pipe is cut in half, what is the new fundamental frequency? 4f0 2f0 f0 f0/2 f0/4

Jeffrey Rodriguez

in Physics

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Kyle Mckinney on November 23, 2018

The fundamental frequency of the pipe is given as:f = v/4LL is equal to the length of the pipeSince L = Lo/2, where Lo is the original length of the pipe, the new frequency would be:f = (v/4)/(Lo/2)f = 2 (v/4Lo) Since v/4Lo = fo, thus:f = 2 fo


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