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How many moles of nh3 can be produced from 15.0 mol of h2 and excess n2?

Jodi Brooks

in Chemistry

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Karen Wright on January 26, 2018

In the first place, we must write a balanced equation for the production of ammonia (NH₃) gas, hydrogen (H₂) and nitrogen gas (N₂): N₂ + 3H₂ → 2NH₃Now, the mole ratio of H₂ : NH₃ is 3 : 2, based on the coefficients of the balanced equation.If the moles of H₂ = 15 moles, then moles of NH₃ produced = (15 mol ÷ 3) × 2 = 10 molThus, the number of moles of NH₃ produced when 15 mol of hydrogen gas combines with the excess of nitrogen gas is 10 mol.


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