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How many grams of (nh4)3po4 are needed to make 0.250 l of 0.150 m (nh4)3po4? hints how many grams of (nh4)3po4 are needed to make 0.250 l of 0.150 m (nh4)3po4? 5.47 g 5.59 g 89.5 g 2.52 x 10-4 g?

Rodney Fox

in Chemistry

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Jodi Brooks on June 30, 2018

There there are a number of ways of expressing the concentration of a solution. This includes molarity. The molarity is expressed as the number of moles of solute per volume of the solution. We calculate the mass of solute by first determining the number of moles needed. And using the molar mass, we can convert to units of mass.Moles (nh4)3po4 = 0.250 L (0.150 M) = 0.0375 moles of (nh4)3po4Mass = 0.0375 mol (nh4)3po4 (149.0867 g / mol) = 5.59 g of (nh4)3po4


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