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How many extraneous solutions does the equation below have? 9/(n^2+1)=(n+3)/4 A)0 B)1 C)2 D)3

Blair Lewis

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Roger Moore on June 4, 2018

To obtain the number of solutions we proceed as follows;9/(n^2+1)=(n+3)/4cross-multiplying the expression we get;9*4=(n^2+1)(n+3)36=n^3+3n^2+n+3this can be written as:n^3+3n^2+n-33=0The above equation is a polynomial of degree 3. So we have 3 solutions.


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