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How long will it take a rock dropped from 2.0 m above the surface of mercury to reach the ground?

Victoria Fowler

in Physics

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Kaitlin Dean on February 21, 2019

The answer is 1.04 s. This is the example of free-fall.Let's start with the kinematics of the formula: d = v1*t + 1/2a*t2where:d - distancev1 - initial distance (in free fall v1 = 0)t - timea - gravitational accelerationWe have:d = 2ma = 3.7 m/s2 (in the mercury)t = ?In free fall, the expression looks like:d = 0*t + 1/2a*t2 = 0 + 1/2a*t2⇒ d = 1/2a*t2Now, from here t can be calculated:t2 = d ÷ 1/2at2 = 2d/a = √(2d/a)We will replace the parameters:t = √(2 * 2 / 3.7)t = √(4/3.7)t = √1.08 t = 1.04 s


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