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# For the simple harmonic motion equation d=5sin((pi/4)t), what is the frequency?

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The standard form of the equation for the sin function is y = Asin(Bx-C) where a is the amplitude, the Period is 2π/B, and the phase shift is equal to Bx-C set to zero. C is obtained in this equation.For the given problem: a is equal to 5, period=2π/B=2π/π/4=8π, the frequency is the reciprocal of the period, which means that the frequency is 1/8π