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For the reaction below, the equilibrium concentrations were found to be [nh3] = 0.250 m ; [h2] = 0.420 m ; [n2] = 0.800 m . give the equilibrium constant expression and use it to calculate the constant. 2 nh3(g) 3 h2(g) + n2(g)

Ross Pratt

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Ralph Lopez on January 24, 2019

The equation for the decomposition of ammonia :2NH3->N2+3H2Equilibrium constant for this equation is:Kc=[N2]([H2]^3)/[NH3]^2a due to the Concentration of N2=0.800 MConcentration H2=0.420 MConcentration of NH3=0.250 MSo Kc=([0.420]^3) *(0.8)/([0.250]^2)= 0.9483264 so the equilibrium constant will be:0.9483264


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