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Find the time th it takes the projectile to reach its maximum height h. express th in terms of v0, ?, and g (the magnitude of the acceleration due to gravity).
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The derivative of h(t) = (-g/2)t2 +v0·t + h0is h'(t) = -gt +v0This is zero at the maximum height, so that the time can be found as 0 = -gt +v0-gt = v0 t = v0/g