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# Find the cube roots of 125(cos 288° + i sin 288°)

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Let r(cos O + i sin O) be a cube root of 125(cos 288 + i sin 288)thenr^3(cos O + i sin O)^3 = 125(cos 288 + i sin 28)so r^3 = 125, and cos 3 + i sin 3O = cos 288 + i sin 288so r = 5 and 3 = 288 + 360 pixels and O = 96 + 120pso a cube root is 5 (cos 96 + i sin 96)I'm a little rusty on this has been a long time.I'm not sure of the other 2 rootssorry can help you more