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Find all solutions in the interval [0, 2π). 7 tan3x - 21 tan x = 0

Kevin Sutter

in Chemistry

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Ross Pratt on April 27, 2018

For the answer to the previous question, I'm going to do a step-by-step on how to solve the problem7 tan^3x - 21 tanx = 0 => 7tanx (tan^2 x - 3) = 0 => tanx = 0 or tan^2 x = 3 => x = 0, π, or tanx = ± √3, that is to say, tanx = √3 or tanx = - √3 tanx = √3 => tanx = tan (π/6) or tan (π + π/6) => x = π/6 or 7π/6 and tanx = - √3 => tanx = tan (π - π/6) or tan (2π - π/6) => x = 5π/6 or 11π/6, The answer would be x = { 0, π/6, 5π/6, π, 7π/6, 11π/6 }.I hope that my answer helped you.


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