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Factor completely 2x3y4 − 8x2y3 + 6xy2. 2(x3y4 − 4x2y3 + 3xy2) 2x(x2y4 − 4xy3 + 3y2) 2xy2(x2y2 − 4xy + 3) Prime

Victoria Fowler

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Jeremy Wood on December 9, 2018

2xy^2(x^2y^2-4xy+3).................................


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