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Evaluate x/y + 3z^2 for x= 2/3, y= 6/7, and z=3 a. 250/9 b. 169/9 c. 9/250 d. 9/169

Curtis Rhodes

in Mathematics

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Kevin Sutter on September 21, 2018

remember that (a/b)/(c/d)=(a/b)(d/c)=(ad)/(bc)(2/3)/(6/7)+3(3)^2=(2/3)(7/6)+3(9)=(2*7)/(3*6)+27=(14/18)+27=(7/9)+27=7/9+243/9=250/9answer is A


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