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Determine the molar solubility of fe(oh)2 in pure water. ksp for fe(oh)2= 4.87 × 10-17

Theresa Perry

in Chemistry

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Jodi Brooks on September 24, 2018

Reply is: solubility molar iron(II) hydroxide 2.3·10⁻⁶ M. Chemical reaction: Fe(OH)₂(s) → Fe2⁺(aq) + 2OH⁻(aq). s(Fe(OH)₂) = ?M. s(Fe(OH)₂) = s(Fe2⁺) = x. s(OH⁻) = 2s(Fe(OH)₂) = 2x. Ksp = s(Fe2⁺) · (s(O⁻))2.Ksp = x · (2x)2.4,87·10⁻1⁷ = 4x3.x = ∛(4,87·10⁻1⁷ ÷ 4).x = 2,3·10⁻⁶ M.


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