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Determine the density of nh3 gas at 435k and 1.00atm

Mindee Nelson

in Chemistry

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Samantha Barber on September 9, 2018

We assume that the gas is ideal. Therefore, we can use the ideal gas equation, which is expressed as:PV=nRT we Can rearrange this equation gives us an expression that corresponds to the density. Do it the following way:PV= nRTP/RT = n/V where n = m/MMP(MM) /RT = m/V = densityDensity = 1.00 (17.03) / 0.08206 (435)Density = 0.48 g / L


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