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Calculate the temperature, in k, of 2.20 moles of gas occupying 3.30 l at 3.50 atm.

Ronald Miller

in Chemistry

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Chelsea Hayes on January 1, 2019

From the idea gas equation PV=nRTT= temperature in kelvinR=gas cosntant(0.0821 atm/k/mol)P=pressure(3.5 atm)V=volume of 3.30 Ln=number of moles (2.20 mol)T is, therefore, =PV/nRT={(3.50 x3.30) /(2.20 x 0.0821)}=k 63.95


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