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Calculate the root mean square velocity of nitrogen molecules at 25 C. a. 515 m/s b. 149 c . 729 got wrong d. 297 m/s

William Cain

in Physics

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Kathy Robinson on March 7, 2018

the root mean square= square root of ( 3RT/M) R = 8.314 J/K/mole T = 25 + 273 = 298 K M = molecular mas of N2 in kg = 28 X 10^-3 kg putting the values... of the root mean square = square root of ( 3 X 8.314 X 298/28 X 10^-3) = square root of ( 265454.143) = 515.2 m/sso option is righthope this helps


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