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Ag has an anomalous electron configuration. write the observed electron configuration of ag. express your answer in complete form in order of increasing orbital energy. for example, 1s22s2 should be entered as 1s^22s^2.

Roger Moore

in Chemistry

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Jeremy Wood on January 28, 2018

In Silver, the orbitals 4d will be completely full. That means you don't have two electrons in the orbital 5s. The electronic settings of Silver :Ag (47) = 1s^2 2^2 2^6 3s^2 3p^6 4s^2 3d^10 4p^6 5s^1 4d^10


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