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# A sample of 76 g of NaCl is dissolved to make 1 L of solution. What is the molarity of the solution? Show your work.

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The answer is 1.3 mol of NaCl.We know that there are 76 g of NaCl in 1 liter of the solution.But we need to calculate the molarity.In the first place, we're going to need the molar mass of NaCl, which is the sum of the ratio of the atomic masses of Na (22.99 g/mol) and Cl (35.45 g/mol):Mr(NaCl) = A(Na) + A(Cl) = 22.99 g/mol + 35.45 g/mol = 58.44 g/mol.This tells us that there are 58.44 g of NaCl in 1 mol. So, how many moles will be of 76 g of NaCl)? The use of the ratio:58.44 g : 1 mole = 76 g : xAfter cross product:x * 58.44 g = 1 mol * 76 gx = 76 / 58.44 mol = 1.3 mol