Hot Student Stories
top-5-grammar-and-spelling-checkers-to-rock-in-2019

A plane is located at C on the diagram. There are two towers located at A and B. The distance between the towers is 7,600 feet, and the angles of elevation are given. a. Find BC, the distance from Tower 2 to the plane, to the nearest foot. b. Find CD, the height of the plane from the ground, to the nearest foot. Please show work! It is not multiple choice. Download png

Ralph Lopez

in Mathematics

follow
followin
1 answer
49 views

1 answer


Mindee Nelson on October 11, 2018

Part a) Find BC, the distance from Tower 2 to the plane, to the nearest foot.in the triangle ACDsin16=CD/(7600+BD)--------> CD=sin16*(7600+BD)---------> equation 1 in the triangle BCDsin24=CD/BD-----------> CD=sin24*BD---------------> equation 2equation 1=equation 2sin16*(7600+BD)=sin24*BD-----> sin16*7600+sin16*BD=sin24*BDsin24*BD-sin16*BD=sin16*7600----> BD=[sin16*7600]/[sin24-sin16]BD=15979 ftin the triangle BCDcos24=BD/BC---------> BC=BD/cos24-------> 15979/cos24-------> 17491BC=17491 ftthe answer part 1) BC is 17491 ftPart 2) Find CD, the height of the plane of the earth, to the nearest foot.CD=sin24*BD ( remember equation 2)BD=15979 ftCD=sin24*15979 -----------> CD=6499 ftthe answer part 2) CD is 6499 ft


Add you answer