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A container of gas is at a pressure of 1.3x10^5 Pa and a volume of 6 m^3. How much work is done by the gas if it expands at a constant pressure to twice its initial volume.

Annie Barnes

in Physics

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Mindee Nelson on October 17, 2018

In thermodynamics, the work of a system at constant pressure conditions is equal to the product of the pressure and the volume change. It is expressed in the following way:W = P(V2 - V1)W = 1.3x10^5 (2x6 - 6 )W = 780000 JHope this answers the question. Have a good day.


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