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A ball with a horizontal speed of 1.25 m/s rolls off a bench 1.00 m above the floor. part a how long will it take the ball to hit the floor?

Eric Morgan

in Physics

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Jessie Thompson on November 16, 2018

Working from the formula:s = v*t + 0.5*a*t^2where: y = vertical distance = -1 m v = initial velocity = 1.25 m/s a = acceleration = 9.81 m/s^2 t = timeRequired: tSolution:y = v*t + 0.5*a*t^21 = (1.25)*t + 0.5*9.81*t^20 = -1 + 1.25 t + 4.905 t^2Applying completing the square, we gett = 0.342 s - 0.597 sTechnically, we don't have time with negative value. Therefore, the answer is t = 0.342 seconds


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